What are the solutions to the equation 5v^2-20v=0 ?

The solutions to the equation 5v^2-20v=0 are v=4,v=0

Find the zeros of 5v^2-20v=0

The zeros of 5v^2-20v=0 are v=4,v=0

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5 v^{2} - 20 v = 0

v = 4, v = 0

Solution steps

5 v^{2} - 20 v = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

(- 20)^{2} - 4 \cdot 5 \cdot 0 = 20

v_{1, 2} = \frac{- ( - 20 ) \pm 20}{2 \cdot 5}

Separate the solutions

v_{1} = \frac{- ( - 20 ) + 20}{2 \cdot 5}, v_{2} = \frac{- ( - 20 ) - 20}{2 \cdot 5}

v = \frac{- ( - 20 ) + 20}{2 \cdot 5} : 4

v = \frac{- ( - 20 ) - 20}{2 \cdot 5} : 0

The solutions to the quadratic equation are:

v = 4, v = 0

(n) = n^{2} - 4 n + 20

- x^{2} + 7 x = 11.25

w^{2} - 10 w

r^{2} + r - 4 = 0

(h + 1)^{2} = 16

What are the solutions to the equation 5v^2-20v=0 ?
The solutions to the equation 5v^2-20v=0 are v=4,v=0
Find the zeros of 5v^2-20v=0
The zeros of 5v^2-20v=0 are v=4,v=0