What are the solutions to the equation (h+1)^2=16 ?

The solutions to the equation (h+1)^2=16 are h=3,h=-5

Find the zeros of (h+1)^2=16

The zeros of (h+1)^2=16 are h=3,h=-5

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(h + 1)^{2} = 16

h = 3, h = - 5

Solution steps

(h + 1)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

h + 1 = 16 : h = 3

Solve

h + 1 = - 16 : h = - 5

The solutions to the quadratic equation are:

h = 3, h = - 5

x^{2} + 11 x = 180

a^{2} + 7 a = 0

x^{2} + (\frac{3}{2})^{2} = 9

(x + 9)^{2} + 7 (x + 9) + 6 = 0

3 (x + 9)^{2} = 8

What are the solutions to the equation (h+1)^2=16 ?
The solutions to the equation (h+1)^2=16 are h=3,h=-5
Find the zeros of (h+1)^2=16
The zeros of (h+1)^2=16 are h=3,h=-5