What are the solutions to the equation (x+9)^2+7(x+9)+6=0 ?

The solutions to the equation (x+9)^2+7(x+9)+6=0 are x=-10,x=-15

Find the zeros of (x+9)^2+7(x+9)+6=0

The zeros of (x+9)^2+7(x+9)+6=0 are x=-10,x=-15

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(x + 9)^{2} + 7 (x + 9) + 6 = 0

x = - 10, x = - 15

Solution steps

(x + 9)^{2} + 7 (x + 9) + 6 = 0

Expand

(x + 9)^{2} + 7 (x + 9) + 6 : x^{2} + 25 x + 150

x^{2} + 25 x + 150 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 1 \cdot 150}{2 \cdot 1}

2 5^{2} - 4 \cdot 1 \cdot 150 = 5

x_{1, 2} = \frac{- 25 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 25 + 5}{2 \cdot 1}, x_{2} = \frac{- 25 - 5}{2 \cdot 1}

x = \frac{- 25 + 5}{2 \cdot 1} : - 10

x = \frac{- 25 - 5}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = - 10, x = - 15

3 (x + 9)^{2} = 8

2 x^{2} - 2000 x + 100000 = 0

16 x^{2} = 40 x - 25

5 x^{2} - 10 x - 4 = 0

x^{2} + 1 2^{2} = 1 8^{2}

What are the solutions to the equation (x+9)^2+7(x+9)+6=0 ?
The solutions to the equation (x+9)^2+7(x+9)+6=0 are x=-10,x=-15
Find the zeros of (x+9)^2+7(x+9)+6=0
The zeros of (x+9)^2+7(x+9)+6=0 are x=-10,x=-15