What are the solutions to the equation 2(x-3)^2-40=0 ?

The solutions to the equation 2(x-3)^2-40=0 are x=2sqrt(5)+3,x=-2sqrt(5)+3

Find the zeros of 2(x-3)^2-40=0

The zeros of 2(x-3)^2-40=0 are x=2sqrt(5)+3,x=-2sqrt(5)+3

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2 (x - 3)^{2} - 40 = 0

x = 25 + 3, x = - 25 + 3

Decimal Notation

x = 7.47213 \dots, x = - 1.47213 \dots

Solution steps

2 (x - 3)^{2} - 40 = 0

Move

40

to the right side

2 (x - 3)^{2} = 40

Divide both sides by

2

(x - 3)^{2} = 20

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 20 : x = 25 + 3

Solve

x - 3 = - 20 : x = - 25 + 3

The solutions to the quadratic equation are:

x = 25 + 3, x = - 25 + 3

- x^{2} + 2 x - 3

y, x = z^{2} + y^{2}

2 s^{2} - 5 s = 3

3 x^{2} + 3 x = 2 x - 1

(λ^{2} - 14) - 20 = λ

What are the solutions to the equation 2(x-3)^2-40=0 ?
The solutions to the equation 2(x-3)^2-40=0 are x=2sqrt(5)+3,x=-2sqrt(5)+3
Find the zeros of 2(x-3)^2-40=0
The zeros of 2(x-3)^2-40=0 are x=2sqrt(5)+3,x=-2sqrt(5)+3