What are the solutions to the equation 2s^2-5s=3 ?

The solutions to the equation 2s^2-5s=3 are s=3,s=-1/2

Find the zeros of 2s^2-5s=3

The zeros of 2s^2-5s=3 are s=3,s=-1/2

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2 s^{2} - 5 s = 3

s = 3, s = - \frac{1}{2}

Solution steps

2 s^{2} - 5 s = 3

Move

3

to the left side

2 s^{2} - 5 s - 3 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 3) = 7

s_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 2}

Separate the solutions

s_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 2}, s_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 2}

s = \frac{- ( - 5 ) + 7}{2 \cdot 2} : 3

s = \frac{- ( - 5 ) - 7}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

s = 3, s = - \frac{1}{2}

3 x^{2} + 3 x = 2 x - 1

(λ^{2} - 14) - 20 = λ

x, x^{2} - 2 x = m^{2} + 2 m

- 3 x^{2} + (7 k^{2} - 3) x + 7 = 0

w, z = - 2 w^{2}

What are the solutions to the equation 2s^2-5s=3 ?
The solutions to the equation 2s^2-5s=3 are s=3,s=-1/2
Find the zeros of 2s^2-5s=3
The zeros of 2s^2-5s=3 are s=3,s=-1/2