What are the solutions to the equation (x+1)^3=(x+2)^3-1 ?

The solutions to the equation (x+1)^3=(x+2)^3-1 are x=-2,x=-1

Find the zeros of (x+1)^3=(x+2)^3-1

The zeros of (x+1)^3=(x+2)^3-1 are x=-2,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 1)^{3} = (x + 2)^{3} - 1

x = - 2, x = - 1

Solution steps

(x + 1)^{3} = (x + 2)^{3} - 1

Expand

(x + 1)^{3} : x^{3} + 3 x^{2} + 3 x + 1

Expand

(x + 2)^{3} - 1 : x^{3} + 6 x^{2} + 12 x + 7

x^{3} + 3 x^{2} + 3 x + 1 = x^{3} + 6 x^{2} + 12 x + 7

Subtract

x^{3} + 6 x^{2} + 12 x + 7

from both sides

x^{3} + 3 x^{2} + 3 x + 1 - (x^{3} + 6 x^{2} + 12 x + 7) = x^{3} + 6 x^{2} + 12 x + 7 - (x^{3} + 6 x^{2} + 12 x + 7)

Simplify

- 3 x^{2} - 9 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 ( - 3 ) ( - 6 )}{2 ( - 3 )}

(- 9)^{2} - 4 (- 3) (- 6) = 3

x_{1, 2} = \frac{- ( - 9 ) \pm 3}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 3}{2 ( - 3 )}, x_{2} = \frac{- ( - 9 ) - 3}{2 ( - 3 )}

x = \frac{- ( - 9 ) + 3}{2 ( - 3 )} : - 2

x = \frac{- ( - 9 ) - 3}{2 ( - 3 )} : - 1

The solutions to the quadratic equation are:

x = - 2, x = - 1

x^{2} + 3 x = 20 x

6 - \frac{x ^{2}}{4} = 2

p^{2} + 16 p - 22 = 0

3 x (x - 2) = 9 x^{2} - 7 x

16 x = x^{2}

What are the solutions to the equation (x+1)^3=(x+2)^3-1 ?
The solutions to the equation (x+1)^3=(x+2)^3-1 are x=-2,x=-1
Find the zeros of (x+1)^3=(x+2)^3-1
The zeros of (x+1)^3=(x+2)^3-1 are x=-2,x=-1