What are the solutions to the equation x^2+3x=20x ?

The solutions to the equation x^2+3x=20x are x=17,x=0

Find the zeros of x^2+3x=20x

The zeros of x^2+3x=20x are x=17,x=0

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x^{2} + 3 x = 20 x

x = 17, x = 0

Solution steps

x^{2} + 3 x = 20 x

Move

20 x

to the left side

x^{2} - 17 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 17)^{2} - 4 \cdot 1 \cdot 0 = 17

x_{1, 2} = \frac{- ( - 17 ) \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 17}{2 \cdot 1}, x_{2} = \frac{- ( - 17 ) - 17}{2 \cdot 1}

x = \frac{- ( - 17 ) + 17}{2 \cdot 1} : 17

x = \frac{- ( - 17 ) - 17}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 17, x = 0

6 - \frac{x ^{2}}{4} = 2

p^{2} + 16 p - 22 = 0

3 x (x - 2) = 9 x^{2} - 7 x

16 x = x^{2}

4 (x - 3)^{2} = 144

What are the solutions to the equation x^2+3x=20x ?
The solutions to the equation x^2+3x=20x are x=17,x=0
Find the zeros of x^2+3x=20x
The zeros of x^2+3x=20x are x=17,x=0