What are the solutions to the equation 4(x-3)^2=144 ?

The solutions to the equation 4(x-3)^2=144 are x=9,x=-3

Find the zeros of 4(x-3)^2=144

The zeros of 4(x-3)^2=144 are x=9,x=-3

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4 (x - 3)^{2} = 144

x = 9, x = - 3

Solution steps

4 (x - 3)^{2} = 144

Divide both sides by

4

(x - 3)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 36 : x = 9

Solve

x - 3 = - 36 : x = - 3

The solutions to the quadratic equation are:

x = 9, x = - 3

- x^{2} + 3 x + 3 = 0

0 = 5 x^{2} - 4

x^{2} - 10 x + 20

6 x^{2} + 60 x + 246 = 0

8 - y = \frac{( y - 2 ) ^{2}}{3}

What are the solutions to the equation 4(x-3)^2=144 ?
The solutions to the equation 4(x-3)^2=144 are x=9,x=-3
Find the zeros of 4(x-3)^2=144
The zeros of 4(x-3)^2=144 are x=9,x=-3