What are the solutions to the equation 0=5x^2-4 ?

The solutions to the equation 0=5x^2-4 are x= 2/(sqrt(5)),x=-2/(sqrt(5))

Find the zeros of 0=5x^2-4

The zeros of 0=5x^2-4 are x= 2/(sqrt(5)),x=-2/(sqrt(5))

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0 = 5 x^{2} - 4

x = \frac{2}{5}, x = - \frac{2}{5}

Solution steps

0 = 5 x^{2} - 4

Switch sides

5 x^{2} - 4 = 0

Move

4

to the right side

5 x^{2} = 4

Divide both sides by

5

x^{2} = \frac{4}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{4}{5}, x = - \frac{4}{5}

\frac{4}{5} = \frac{2}{5}

- \frac{4}{5} = - \frac{2}{5}

x = \frac{2}{5}, x = - \frac{2}{5}

x^{2} - 10 x + 20

6 x^{2} + 60 x + 246 = 0

8 - y = \frac{( y - 2 ) ^{2}}{3}

(5 x + 9)^{2} + 9 = 49

\frac{1}{3} x^{2} = 12

What are the solutions to the equation 0=5x^2-4 ?
The solutions to the equation 0=5x^2-4 are x= 2/(sqrt(5)),x=-2/(sqrt(5))
Find the zeros of 0=5x^2-4
The zeros of 0=5x^2-4 are x= 2/(sqrt(5)),x=-2/(sqrt(5))