What are the solutions to the equation (5x+9)^2+9=49 ?

The solutions to the equation (5x+9)^2+9=49 are x=(2sqrt(10)-9)/5 ,x=(-2sqrt(10)-9)/5

Find the zeros of (5x+9)^2+9=49

The zeros of (5x+9)^2+9=49 are x=(2sqrt(10)-9)/5 ,x=(-2sqrt(10)-9)/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(5 x + 9)^{2} + 9 = 49

x = \frac{2 10 - 9}{5}, x = \frac{- 2 10 - 9}{5}

Decimal Notation

x = - 0.53508 \dots, x = - 3.06491 \dots

Solution steps

(5 x + 9)^{2} + 9 = 49

Move

9

to the right side

(5 x + 9)^{2} = 40

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x + 9 = 40 : x = \frac{2 10 - 9}{5}

Solve

5 x + 9 = - 40 : x = \frac{- 2 10 - 9}{5}

The solutions to the quadratic equation are:

x = \frac{2 10 - 9}{5}, x = \frac{- 2 10 - 9}{5}

\frac{1}{3} x^{2} = 12

x, x^{2} + 2 x y + 3 y^{2} = 4

8 n^{2} - 16 n + 66 = - 2

5 = x^{2} + 1

7 r^{2} - 14 r = - 7

What are the solutions to the equation (5x+9)^2+9=49 ?
The solutions to the equation (5x+9)^2+9=49 are x=(2sqrt(10)-9)/5 ,x=(-2sqrt(10)-9)/5
Find the zeros of (5x+9)^2+9=49
The zeros of (5x+9)^2+9=49 are x=(2sqrt(10)-9)/5 ,x=(-2sqrt(10)-9)/5