What are the solutions to the equation x(2x-9)=-10 ?

The solutions to the equation x(2x-9)=-10 are x= 5/2 ,x=2

Find the zeros of x(2x-9)=-10

The zeros of x(2x-9)=-10 are x= 5/2 ,x=2

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x (2 x - 9) = - 10

x = \frac{5}{2}, x = 2

Decimal Notation

x = 2.5, x = 2

Solution steps

x (2 x - 9) = - 10

Expand

x (2 x - 9) : 2 x^{2} - 9 x

2 x^{2} - 9 x = - 10

Move

10

to the left side

2 x^{2} - 9 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 \cdot 10}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 \cdot 10 = 1

x_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 1}{2 \cdot 2}, x_{2} = \frac{- ( - 9 ) - 1}{2 \cdot 2}

x = \frac{- ( - 9 ) + 1}{2 \cdot 2} : \frac{5}{2}

x = \frac{- ( - 9 ) - 1}{2 \cdot 2} : 2

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = 2

m^{2} + 12 m = 52

y^{2} - 5 y = 14

2 x^{2} + 128 x - 4096 = 0

4 (7 - 7 x^{2}) = 7

2 x^{2} + x - 3 = 0

What are the solutions to the equation x(2x-9)=-10 ?
The solutions to the equation x(2x-9)=-10 are x= 5/2 ,x=2
Find the zeros of x(2x-9)=-10
The zeros of x(2x-9)=-10 are x= 5/2 ,x=2