What are the solutions to the equation 12x^2-x-2=0 ?

The solutions to the equation 12x^2-x-2=0 are x=(1+sqrt(97))/(24),x=(1-sqrt(97))/(24)

Find the zeros of 12x^2-x-2=0

The zeros of 12x^2-x-2=0 are x=(1+sqrt(97))/(24),x=(1-sqrt(97))/(24)

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12 x^{2} - x - 2 = 0

x = \frac{1 + 97}{24}, x = \frac{1 - 97}{24}

Solution steps

12 x^{2} - x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 12 ( - 2 )}{2 \cdot 12}

(- 1)^{2} - 4 \cdot 12 (- 2) = 97

x_{1, 2} = \frac{- ( - 1 ) \pm 97}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 97}{2 \cdot 12}, x_{2} = \frac{- ( - 1 ) - 97}{2 \cdot 12}

x = \frac{- ( - 1 ) + 97}{2 \cdot 12} : \frac{1 + 97}{24}

x = \frac{- ( - 1 ) - 97}{2 \cdot 12} : \frac{1 - 97}{24}

The solutions to the quadratic equation are:

x = \frac{1 + 97}{24}, x = \frac{1 - 97}{24}

6 x^{2} - 42 x + 12 = 0

- 2 x^{2} + 7 x - 2 = 0

x^{2} = 20 x - 36

15 x^{2} + 14 x + 3 = 0

(x) = - 4 x + 0.05 x^{2} + 240

What are the solutions to the equation 12x^2-x-2=0 ?
The solutions to the equation 12x^2-x-2=0 are x=(1+sqrt(97))/(24),x=(1-sqrt(97))/(24)
Find the zeros of 12x^2-x-2=0
The zeros of 12x^2-x-2=0 are x=(1+sqrt(97))/(24),x=(1-sqrt(97))/(24)