What are the solutions to the equation -2x^2+7x-2=0 ?

The solutions to the equation -2x^2+7x-2=0 are x=(7-sqrt(33))/4 ,x=(7+sqrt(33))/4

Find the zeros of -2x^2+7x-2=0

The zeros of -2x^2+7x-2=0 are x=(7-sqrt(33))/4 ,x=(7+sqrt(33))/4

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- 2 x^{2} + 7 x - 2 = 0

x = \frac{7 - 33}{4}, x = \frac{7 + 33}{4}

Solution steps

- 2 x^{2} + 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 2 ) ( - 2 )}{2 ( - 2 )}

7^{2} - 4 (- 2) (- 2) = 33

x_{1, 2} = \frac{- 7 \pm 33}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 7 + 33}{2 ( - 2 )}, x_{2} = \frac{- 7 - 33}{2 ( - 2 )}

x = \frac{- 7 + 33}{2 ( - 2 )} : \frac{7 - 33}{4}

x = \frac{- 7 - 33}{2 ( - 2 )} : \frac{7 + 33}{4}

The solutions to the quadratic equation are:

x = \frac{7 - 33}{4}, x = \frac{7 + 33}{4}

x^{2} = 20 x - 36

15 x^{2} + 14 x + 3 = 0

(x) = - 4 x + 0.05 x^{2} + 240

(7 x + 5)^{2} + 7 (7 x + 5) = 0

x^{2} - 3 x - 6 = 2 x + 30

What are the solutions to the equation -2x^2+7x-2=0 ?
The solutions to the equation -2x^2+7x-2=0 are x=(7-sqrt(33))/4 ,x=(7+sqrt(33))/4
Find the zeros of -2x^2+7x-2=0
The zeros of -2x^2+7x-2=0 are x=(7-sqrt(33))/4 ,x=(7+sqrt(33))/4