What are the solutions to the equation 2x^2=4x-6 ?

The solutions to the equation 2x^2=4x-6 are x=1+sqrt(2)i,x=1-sqrt(2)i

Find the zeros of 2x^2=4x-6

The zeros of 2x^2=4x-6 are x=1+sqrt(2)i,x=1-sqrt(2)i

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2 x^{2} = 4 x - 6

x = 1 + 2 i, x = 1 - 2 i

Solution steps

2 x^{2} = 4 x - 6

Move

6

to the left side

2 x^{2} + 6 = 4 x

Move

4 x

to the left side

2 x^{2} + 6 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 4 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

Simplify

(- 4)^{2} - 4 \cdot 2 \cdot 6 : 42 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 2 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 2 i}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 4 2 i}{2 \cdot 2}

x = \frac{- ( - 4 ) + 4 2 i}{2 \cdot 2} : 1 + 2 i

x = \frac{- ( - 4 ) - 4 2 i}{2 \cdot 2} : 1 - 2 i

The solutions to the quadratic equation are:

x = 1 + 2 i, x = 1 - 2 i

1 - x^{2} = 0

5 (x + 3)^{2} - 7 = 68

4 x (x - 1) = 3

t, f = 2 t - 3 f (t^{2})

y^{2} + y - 42 = 0

What are the solutions to the equation 2x^2=4x-6 ?
The solutions to the equation 2x^2=4x-6 are x=1+sqrt(2)i,x=1-sqrt(2)i
Find the zeros of 2x^2=4x-6
The zeros of 2x^2=4x-6 are x=1+sqrt(2)i,x=1-sqrt(2)i