What are the solutions to the equation 4x(x-1)=3 ?

The solutions to the equation 4x(x-1)=3 are x= 3/2 ,x=-1/2

Find the zeros of 4x(x-1)=3

The zeros of 4x(x-1)=3 are x= 3/2 ,x=-1/2

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4 x (x - 1) = 3

x = \frac{3}{2}, x = - \frac{1}{2}

Decimal Notation

x = 1.5, x = - 0.5

Solution steps

4 x (x - 1) = 3

Expand

4 x (x - 1) : 4 x^{2} - 4 x

4 x^{2} - 4 x = 3

Move

3

to the left side

4 x^{2} - 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 (- 3) = 8

x_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 8}{2 \cdot 4}

x = \frac{- ( - 4 ) + 8}{2 \cdot 4} : \frac{3}{2}

x = \frac{- ( - 4 ) - 8}{2 \cdot 4} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - \frac{1}{2}

t, f = 2 t - 3 f (t^{2})

y^{2} + y - 42 = 0

(x - 6) (x - 8) = - 1

- 3 x^{2} - 18 x - 26 = 0

0.2 x^{2} - 6 x + 80 = 0.6 x^{2} - 12 x + 80

What are the solutions to the equation 4x(x-1)=3 ?
The solutions to the equation 4x(x-1)=3 are x= 3/2 ,x=-1/2
Find the zeros of 4x(x-1)=3
The zeros of 4x(x-1)=3 are x= 3/2 ,x=-1/2