What are the solutions to the equation A=x^2+12x+27 ?

The solutions to the equation A=x^2+12x+27 are x=-6+sqrt(A+9),x=-sqrt(A+9)-6

Find the zeros of A=x^2+12x+27

The zeros of A=x^2+12x+27 are x=-6+sqrt(A+9),x=-sqrt(A+9)-6

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A = x^{2} + 12 x + 27

x = - 6 + A + 9, x = - A + 9 - 6

Solution steps

A = x^{2} + 12 x + 27

Switch sides

x^{2} + 12 x + 27 = A

Move

A

to the left side

x^{2} + 12 x + 27 - A = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( 27 - A )}{2 \cdot 1}

Simplify

1 2^{2} - 4 \cdot 1 \cdot (27 - A) : 2 A + 9

x_{1, 2} = \frac{- 12 \pm 2 A + 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 A + 9}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 A + 9}{2 \cdot 1}

x = \frac{- 12 + 2 A + 9}{2 \cdot 1} : - 6 + A + 9

x = \frac{- 12 - 2 A + 9}{2 \cdot 1} : - A + 9 - 6

The solutions to the quadratic equation are:

x = - 6 + A + 9, x = - A + 9 - 6

x^{2} - 6 x + 15 = 10

0.02 x^{2} - 0.3 x = 20

4 x^{2} + 10 x - 4 = 0

(x + 5) 2 + 6 = 2 (x + 4) (x + 2)

16 x^{2} = 11

What are the solutions to the equation A=x^2+12x+27 ?
The solutions to the equation A=x^2+12x+27 are x=-6+sqrt(A+9),x=-sqrt(A+9)-6
Find the zeros of A=x^2+12x+27
The zeros of A=x^2+12x+27 are x=-6+sqrt(A+9),x=-sqrt(A+9)-6