What are the solutions to the equation x^2+12x-364=0 ?

The solutions to the equation x^2+12x-364=0 are x=14,x=-26

Find the zeros of x^2+12x-364=0

The zeros of x^2+12x-364=0 are x=14,x=-26

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x^{2} + 12 x - 364 = 0

x = 14, x = - 26

Solution steps

x^{2} + 12 x - 364 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( - 364 )}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot (- 364) = 40

x_{1, 2} = \frac{- 12 \pm 40}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 40}{2 \cdot 1}, x_{2} = \frac{- 12 - 40}{2 \cdot 1}

x = \frac{- 12 + 40}{2 \cdot 1} : 14

x = \frac{- 12 - 40}{2 \cdot 1} : - 26

The solutions to the quadratic equation are:

x = 14, x = - 26

x^{2} + 12 x - 3

(a x + 5 b)^{2} - (b x + 5 a)^{2} = 0

x^{2} - 203 x + 252 = 0

x^{2} + 3 x - 18 = 0

x^{2} + 12 x + 20

What are the solutions to the equation x^2+12x-364=0 ?
The solutions to the equation x^2+12x-364=0 are x=14,x=-26
Find the zeros of x^2+12x-364=0
The zeros of x^2+12x-364=0 are x=14,x=-26