What are the solutions to the equation x^2-20sqrt(3)x+252=0 ?

The solutions to the equation x^2-20sqrt(3)x+252=0 are x=14sqrt(3),x=6sqrt(3)

Find the zeros of x^2-20sqrt(3)x+252=0

The zeros of x^2-20sqrt(3)x+252=0 are x=14sqrt(3),x=6sqrt(3)

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x^{2} - 203 x + 252 = 0

x = 143, x = 63

Solution steps

x^{2} - 203 x + 252 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 3 ) \pm ( - 20 3 ) ^{2} - 4 \cdot 1 \cdot 252}{2 \cdot 1}

(- 203)^{2} - 4 \cdot 1 \cdot 252 = 83

x_{1, 2} = \frac{- ( - 20 3 ) \pm 8 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 3 ) + 8 3}{2 \cdot 1}, x_{2} = \frac{- ( - 20 3 ) - 8 3}{2 \cdot 1}

x = \frac{- ( - 20 3 ) + 8 3}{2 \cdot 1} : 143

x = \frac{- ( - 20 3 ) - 8 3}{2 \cdot 1} : 63

The solutions to the quadratic equation are:

x = 143, x = 63

x^{2} + 3 x - 18 = 0

x^{2} + 12 x + 20

x^{2} + 12 x + 13

8 y + 3 y^{2} = 35

- 2 x^{2} + 8 x - 3 = - 2 x + 5

What are the solutions to the equation x^2-20sqrt(3)x+252=0 ?
The solutions to the equation x^2-20sqrt(3)x+252=0 are x=14sqrt(3),x=6sqrt(3)
Find the zeros of x^2-20sqrt(3)x+252=0
The zeros of x^2-20sqrt(3)x+252=0 are x=14sqrt(3),x=6sqrt(3)