What are the solutions to the equation 12x^2+13x=14 ?

The solutions to the equation 12x^2+13x=14 are x= 2/3 ,x=-7/4

Find the zeros of 12x^2+13x=14

The zeros of 12x^2+13x=14 are x= 2/3 ,x=-7/4

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12 x^{2} + 13 x = 14

x = \frac{2}{3}, x = - \frac{7}{4}

Solution steps

12 x^{2} + 13 x = 14

Move

14

to the left side

12 x^{2} + 13 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 12 ( - 14 )}{2 \cdot 12}

1 3^{2} - 4 \cdot 12 (- 14) = 29

x_{1, 2} = \frac{- 13 \pm 29}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 13 + 29}{2 \cdot 12}, x_{2} = \frac{- 13 - 29}{2 \cdot 12}

x = \frac{- 13 + 29}{2 \cdot 12} : \frac{2}{3}

x = \frac{- 13 - 29}{2 \cdot 12} : - \frac{7}{4}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - \frac{7}{4}

x^{2} + 25 x + 36 = 0

9 y (1 - y) = 2

y, y^{2} = x (x - 2) (x + 3)

18 x^{2} - 6 x + 2 = 0

2 r^{2} + 11 r + 15 = 0

What are the solutions to the equation 12x^2+13x=14 ?
The solutions to the equation 12x^2+13x=14 are x= 2/3 ,x=-7/4
Find the zeros of 12x^2+13x=14
The zeros of 12x^2+13x=14 are x= 2/3 ,x=-7/4