What are the solutions to the equation 9y(1-y)=2 ?

The solutions to the equation 9y(1-y)=2 are y= 1/3 ,y= 2/3

Find the zeros of 9y(1-y)=2

The zeros of 9y(1-y)=2 are y= 1/3 ,y= 2/3

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9 y (1 - y) = 2

y = \frac{1}{3}, y = \frac{2}{3}

Solution steps

9 y (1 - y) = 2

Expand

9 y (1 - y) : 9 y - 9 y^{2}

9 y - 9 y^{2} = 2

Move

2

to the left side

9 y - 9 y^{2} - 2 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 9 y^{2} + 9 y - 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 9 ) ( - 2 )}{2 ( - 9 )}

9^{2} - 4 (- 9) (- 2) = 3

y_{1, 2} = \frac{- 9 \pm 3}{2 ( - 9 )}

Separate the solutions

y_{1} = \frac{- 9 + 3}{2 ( - 9 )}, y_{2} = \frac{- 9 - 3}{2 ( - 9 )}

y = \frac{- 9 + 3}{2 ( - 9 )} : \frac{1}{3}

y = \frac{- 9 - 3}{2 ( - 9 )} : \frac{2}{3}

The solutions to the quadratic equation are:

y = \frac{1}{3}, y = \frac{2}{3}

y, y^{2} = x (x - 2) (x + 3)

18 x^{2} - 6 x + 2 = 0

2 r^{2} + 11 r + 15 = 0

(a - 1) x^{2} - (2 a - 3) x - 2 = 0

x + x^{2} - 5 = 0

What are the solutions to the equation 9y(1-y)=2 ?
The solutions to the equation 9y(1-y)=2 are y= 1/3 ,y= 2/3
Find the zeros of 9y(1-y)=2
The zeros of 9y(1-y)=2 are y= 1/3 ,y= 2/3