What are the solutions to the equation x+x^2-5=0 ?

The solutions to the equation x+x^2-5=0 are x=(-1+sqrt(21))/2 ,x=(-1-sqrt(21))/2

Find the zeros of x+x^2-5=0

The zeros of x+x^2-5=0 are x=(-1+sqrt(21))/2 ,x=(-1-sqrt(21))/2

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x + x^{2} - 5 = 0

x = \frac{- 1 + 21}{2}, x = \frac{- 1 - 21}{2}

Decimal Notation

x = 1.79128 \dots, x = - 2.79128 \dots

Solution steps

x + x^{2} - 5 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 5) = 21

x_{1, 2} = \frac{- 1 \pm 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 21}{2 \cdot 1}, x_{2} = \frac{- 1 - 21}{2 \cdot 1}

x = \frac{- 1 + 21}{2 \cdot 1} : \frac{- 1 + 21}{2}

x = \frac{- 1 - 21}{2 \cdot 1} : \frac{- 1 - 21}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 21}{2}, x = \frac{- 1 - 21}{2}

4 x^{2} - 101 x + 25 = 0

2 + 6 t - 4.9 t^{2} = 0

(s + 3) (s + 5) = 0

(5 x + 2) (5 x - 2) = (A + B) (A - B)

(x + 2)^{2} = 8 + x

What are the solutions to the equation x+x^2-5=0 ?
The solutions to the equation x+x^2-5=0 are x=(-1+sqrt(21))/2 ,x=(-1-sqrt(21))/2
Find the zeros of x+x^2-5=0
The zeros of x+x^2-5=0 are x=(-1+sqrt(21))/2 ,x=(-1-sqrt(21))/2