What are the solutions to the equation 2x^2+15x-23=2x ?

The solutions to the equation 2x^2+15x-23=2x are x=(-13+sqrt(353))/4 ,x=(-13-sqrt(353))/4

Find the zeros of 2x^2+15x-23=2x

The zeros of 2x^2+15x-23=2x are x=(-13+sqrt(353))/4 ,x=(-13-sqrt(353))/4

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2 x^{2} + 15 x - 23 = 2 x

x = \frac{- 13 + 353}{4}, x = \frac{- 13 - 353}{4}

Decimal Notation

x = 1.44707 \dots, x = - 7.94707 \dots

Solution steps

2 x^{2} + 15 x - 23 = 2 x

Move

2 x

to the left side

2 x^{2} + 13 x - 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 2 ( - 23 )}{2 \cdot 2}

1 3^{2} - 4 \cdot 2 (- 23) = 353

x_{1, 2} = \frac{- 13 \pm 353}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 13 + 353}{2 \cdot 2}, x_{2} = \frac{- 13 - 353}{2 \cdot 2}

x = \frac{- 13 + 353}{2 \cdot 2} : \frac{- 13 + 353}{4}

x = \frac{- 13 - 353}{2 \cdot 2} : \frac{- 13 - 353}{4}

The solutions to the quadratic equation are:

x = \frac{- 13 + 353}{4}, x = \frac{- 13 - 353}{4}

(r - 2) (r + 8) = - 5

h^{2} + 5 h - 700 = 0

6 = 2 (x - 3)^{2} - 1

b (x) = x^{2} - 4 x

- 2 y^{2} - 9 = - 9 y - y^{2}

What are the solutions to the equation 2x^2+15x-23=2x ?
The solutions to the equation 2x^2+15x-23=2x are x=(-13+sqrt(353))/4 ,x=(-13-sqrt(353))/4
Find the zeros of 2x^2+15x-23=2x
The zeros of 2x^2+15x-23=2x are x=(-13+sqrt(353))/4 ,x=(-13-sqrt(353))/4