What are the solutions to the equation 6=2(x-3)^2-1 ?

The solutions to the equation 6=2(x-3)^2-1 are x=sqrt(7/2)+3,x=-sqrt(7/2)+3

Find the zeros of 6=2(x-3)^2-1

The zeros of 6=2(x-3)^2-1 are x=sqrt(7/2)+3,x=-sqrt(7/2)+3

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6 = 2 (x - 3)^{2} - 1

x = \frac{7}{2} + 3, x = - \frac{7}{2} + 3

Decimal Notation

x = 4.87082 \dots, x = 1.12917 \dots

Solution steps

6 = 2 (x - 3)^{2} - 1

Switch sides

2 (x - 3)^{2} - 1 = 6

Move

1

to the right side

2 (x - 3)^{2} = 7

Divide both sides by

2

(x - 3)^{2} = \frac{7}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = \frac{7}{2} : x = \frac{7}{2} + 3

Solve

x - 3 = - \frac{7}{2} : x = - \frac{7}{2} + 3

The solutions to the quadratic equation are:

x = \frac{7}{2} + 3, x = - \frac{7}{2} + 3

b (x) = x^{2} - 4 x

- 2 y^{2} - 9 = - 9 y - y^{2}

8 = \frac{x}{9} 9 x

2 x^{2} + 16 x + 7 = 0

6 x (x - 1) = 28 - 19 x

What are the solutions to the equation 6=2(x-3)^2-1 ?
The solutions to the equation 6=2(x-3)^2-1 are x=sqrt(7/2)+3,x=-sqrt(7/2)+3
Find the zeros of 6=2(x-3)^2-1
The zeros of 6=2(x-3)^2-1 are x=sqrt(7/2)+3,x=-sqrt(7/2)+3