What are the solutions to the equation 2x^2+16x+7=0 ?

The solutions to the equation 2x^2+16x+7=0 are x=(-8+5sqrt(2))/2 ,x=-(8+5sqrt(2))/2

Find the zeros of 2x^2+16x+7=0

The zeros of 2x^2+16x+7=0 are x=(-8+5sqrt(2))/2 ,x=-(8+5sqrt(2))/2

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2 x^{2} + 16 x + 7 = 0

x = \frac{- 8 + 5 2}{2}, x = - \frac{8 + 5 2}{2}

Solution steps

2 x^{2} + 16 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 2 \cdot 7}{2 \cdot 2}

1 6^{2} - 4 \cdot 2 \cdot 7 = 102

x_{1, 2} = \frac{- 16 \pm 10 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 16 + 10 2}{2 \cdot 2}, x_{2} = \frac{- 16 - 10 2}{2 \cdot 2}

x = \frac{- 16 + 10 2}{2 \cdot 2} : \frac{- 8 + 5 2}{2}

x = \frac{- 16 - 10 2}{2 \cdot 2} : - \frac{8 + 5 2}{2}

The solutions to the quadratic equation are:

x = \frac{- 8 + 5 2}{2}, x = - \frac{8 + 5 2}{2}

6 x (x - 1) = 28 - 19 x

0 = 2 x^{2} - 18

3 - x^{2} + 2 x

0 = x (x - 4)

x^{2} = \frac{9}{256}

What are the solutions to the equation 2x^2+16x+7=0 ?
The solutions to the equation 2x^2+16x+7=0 are x=(-8+5sqrt(2))/2 ,x=-(8+5sqrt(2))/2
Find the zeros of 2x^2+16x+7=0
The zeros of 2x^2+16x+7=0 are x=(-8+5sqrt(2))/2 ,x=-(8+5sqrt(2))/2