What are the solutions to the equation 6x(x-1)=28-19x ?

The solutions to the equation 6x(x-1)=28-19x are x= 4/3 ,x=-7/2

Find the zeros of 6x(x-1)=28-19x

The zeros of 6x(x-1)=28-19x are x= 4/3 ,x=-7/2

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6 x (x - 1) = 28 - 19 x

x = \frac{4}{3}, x = - \frac{7}{2}

Solution steps

6 x (x - 1) = 28 - 19 x

Expand

6 x (x - 1) : 6 x^{2} - 6 x

6 x^{2} - 6 x = 28 - 19 x

Move

19 x

to the left side

6 x^{2} + 13 x = 28

Move

28

to the left side

6 x^{2} + 13 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 6 ( - 28 )}{2 \cdot 6}

1 3^{2} - 4 \cdot 6 (- 28) = 29

x_{1, 2} = \frac{- 13 \pm 29}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 13 + 29}{2 \cdot 6}, x_{2} = \frac{- 13 - 29}{2 \cdot 6}

x = \frac{- 13 + 29}{2 \cdot 6} : \frac{4}{3}

x = \frac{- 13 - 29}{2 \cdot 6} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - \frac{7}{2}

0 = 2 x^{2} - 18

3 - x^{2} + 2 x

0 = x (x - 4)

x^{2} = \frac{9}{256}

x^{2} - 21 x - 5 = 0

What are the solutions to the equation 6x(x-1)=28-19x ?
The solutions to the equation 6x(x-1)=28-19x are x= 4/3 ,x=-7/2
Find the zeros of 6x(x-1)=28-19x
The zeros of 6x(x-1)=28-19x are x= 4/3 ,x=-7/2