What are the solutions to the equation x^2-2x-c=0 ?

The solutions to the equation x^2-2x-c=0 are x=1+sqrt(c+1),x=1-sqrt(c+1)

Find the zeros of x^2-2x-c=0

The zeros of x^2-2x-c=0 are x=1+sqrt(c+1),x=1-sqrt(c+1)

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x^{2} - 2 x - c = 0

x = 1 + c + 1, x = 1 - c + 1

Solution steps

x^{2} - 2 x - c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - c )}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot (- c) : 2 1 + c

x_{1, 2} = \frac{- ( - 2 ) \pm 2 1 + c}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 1 + c}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 1 + c}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 1 + c}{2 \cdot 1} : 1 + c + 1

x = \frac{- ( - 2 ) - 2 1 + c}{2 \cdot 1} : 1 - c + 1

The solutions to the quadratic equation are:

x = 1 + c + 1, x = 1 - c + 1

(2 x - 1)^{2} = (x + 4)^{2}

x^{2} - 4.649160568 x + 3.125 = 0

v^{2} + 11 v + 30 = 0

x, f (x - 2) = x^{2} - 1

x, f (x - 2) = x^{2} - 2

What are the solutions to the equation x^2-2x-c=0 ?
The solutions to the equation x^2-2x-c=0 are x=1+sqrt(c+1),x=1-sqrt(c+1)
Find the zeros of x^2-2x-c=0
The zeros of x^2-2x-c=0 are x=1+sqrt(c+1),x=1-sqrt(c+1)