What are the solutions to the equation v^2+11v+30=0 ?

The solutions to the equation v^2+11v+30=0 are v=-5,v=-6

Find the zeros of v^2+11v+30=0

The zeros of v^2+11v+30=0 are v=-5,v=-6

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v^{2} + 11 v + 30 = 0

v = - 5, v = - 6

Solution steps

v^{2} + 11 v + 30 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 30}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 30 = 1

v_{1, 2} = \frac{- 11 \pm 1}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 11 + 1}{2 \cdot 1}, v_{2} = \frac{- 11 - 1}{2 \cdot 1}

v = \frac{- 11 + 1}{2 \cdot 1} : - 5

v = \frac{- 11 - 1}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

v = - 5, v = - 6

x, f (x - 2) = x^{2} - 1

x, f (x - 2) = x^{2} - 2

X^{2} - 12 X + 36 = 0

(x - 2)^{2} = - 1

(x - 2)^{2} = - 7

What are the solutions to the equation v^2+11v+30=0 ?
The solutions to the equation v^2+11v+30=0 are v=-5,v=-6
Find the zeros of v^2+11v+30=0
The zeros of v^2+11v+30=0 are v=-5,v=-6