What are the solutions to the equation X^2-12X+36=0 ?

The solutions to the equation X^2-12X+36=0 are X=6

Find the zeros of X^2-12X+36=0

The zeros of X^2-12X+36=0 are X=6

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X^{2} - 12 X + 36 = 0

X = 6

Solution steps

X^{2} - 12 X + 36 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 36 = 0

X_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 1}

X = \frac{- ( - 12 )}{2 \cdot 1}

\frac{- ( - 12 )}{2 \cdot 1} = 6

X = 6

The solution to the quadratic equation is:

X = 6

(x - 2)^{2} = - 1

(x - 2)^{2} = - 7

(2 x^{2} - 26 x + 72) = 0

x^{2} = \frac{36}{81}

(x - 6)^{2} - 15 = 13

What are the solutions to the equation X^2-12X+36=0 ?
The solutions to the equation X^2-12X+36=0 are X=6
Find the zeros of X^2-12X+36=0
The zeros of X^2-12X+36=0 are X=6