What are the solutions to the equation (2x^2-26x+72)=0 ?

The solutions to the equation (2x^2-26x+72)=0 are x=4,x=9

Find the zeros of (2x^2-26x+72)=0

The zeros of (2x^2-26x+72)=0 are x=4,x=9

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(2 x^{2} - 26 x + 72) = 0

x = 4, x = 9

Solution steps

(2 x^{2} - 26 x + 72) = 0

Factor

2 x^{2} - 26 x + 72 : 2 (x - 4) (x - 9)

2 (x - 4) (x - 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or x - 9 = 0

Solve

x - 4 = 0 : x = 4

Solve

x - 9 = 0 : x = 9

The solutions to the quadratic equation are:

x = 4, x = 9

x^{2} = \frac{36}{81}

(x - 6)^{2} - 15 = 13

- 5 x^{2} - 80 x - 1545 = 0

- 3 x^{2} + 6 x = - 321

300 = 18 x^{2} - 180 x - 3300

What are the solutions to the equation (2x^2-26x+72)=0 ?
The solutions to the equation (2x^2-26x+72)=0 are x=4,x=9
Find the zeros of (2x^2-26x+72)=0
The zeros of (2x^2-26x+72)=0 are x=4,x=9