What are the solutions to the equation 300=18x^2-180x-3300 ?

The solutions to the equation 300=18x^2-180x-3300 are x=20,x=-10

Find the zeros of 300=18x^2-180x-3300

The zeros of 300=18x^2-180x-3300 are x=20,x=-10

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300 = 18 x^{2} - 180 x - 3300

x = 20, x = - 10

Solution steps

300 = 18 x^{2} - 180 x - 3300

Switch sides

18 x^{2} - 180 x - 3300 = 300

Move

300

to the left side

18 x^{2} - 180 x - 3600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 180 ) \pm ( - 180 ) ^{2} - 4 \cdot 18 ( - 3600 )}{2 \cdot 18}

(- 180)^{2} - 4 \cdot 18 (- 3600) = 540

x_{1, 2} = \frac{- ( - 180 ) \pm 540}{2 \cdot 18}

Separate the solutions

x_{1} = \frac{- ( - 180 ) + 540}{2 \cdot 18}, x_{2} = \frac{- ( - 180 ) - 540}{2 \cdot 18}

x = \frac{- ( - 180 ) + 540}{2 \cdot 18} : 20

x = \frac{- ( - 180 ) - 540}{2 \cdot 18} : - 10

The solutions to the quadratic equation are:

x = 20, x = - 10

- 0.05 x^{2} + 16 x + 80 = 0

x, z = - x^{2} - y^{2}

x^{2} - (3 + 1) x + 3 = 0

- 6 x^{2} + 9 x + 24 = 0

- 4 m^{2} - 12 m + 3 = 0

What are the solutions to the equation 300=18x^2-180x-3300 ?
The solutions to the equation 300=18x^2-180x-3300 are x=20,x=-10
Find the zeros of 300=18x^2-180x-3300
The zeros of 300=18x^2-180x-3300 are x=20,x=-10