What are the solutions to the equation (x+1)^2-(x+1)/2 =18 ?

The solutions to the equation (x+1)^2-(x+1)/2 =18 are x= 7/2 ,x=-5

Find the zeros of (x+1)^2-(x+1)/2 =18

The zeros of (x+1)^2-(x+1)/2 =18 are x= 7/2 ,x=-5

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(x + 1)^{2} - \frac{x + 1}{2} = 18

x = \frac{7}{2}, x = - 5

Decimal Notation

x = 3.5, x = - 5

Solution steps

(x + 1)^{2} - \frac{x + 1}{2} = 18

Multiply both sides by

2

2 (x + 1)^{2} - (x + 1) = 36

Expand

2 (x + 1)^{2} - (x + 1) : 2 x^{2} + 3 x + 1

2 x^{2} + 3 x + 1 = 36

Move

36

to the left side

2 x^{2} + 3 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 35 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 35) = 17

x_{1, 2} = \frac{- 3 \pm 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 17}{2 \cdot 2}, x_{2} = \frac{- 3 - 17}{2 \cdot 2}

x = \frac{- 3 + 17}{2 \cdot 2} : \frac{7}{2}

x = \frac{- 3 - 17}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = - 5

x^{2} + 7^{2} = 1 2^{2}

16 x^{2} - 40 = 0

4 x (8 x) + 8 - 12 = 15 x^{2} - 12 (25 + 16)

- 4.9 x^{2} + 16.8 x + 7.6 = 0

w^{2} + 9 = 0

What are the solutions to the equation (x+1)^2-(x+1)/2 =18 ?
The solutions to the equation (x+1)^2-(x+1)/2 =18 are x= 7/2 ,x=-5
Find the zeros of (x+1)^2-(x+1)/2 =18
The zeros of (x+1)^2-(x+1)/2 =18 are x= 7/2 ,x=-5