What are the solutions to the equation 16x^2-40=0 ?

The solutions to the equation 16x^2-40=0 are x=sqrt(5/2),x=-sqrt(5/2)

Find the zeros of 16x^2-40=0

The zeros of 16x^2-40=0 are x=sqrt(5/2),x=-sqrt(5/2)

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16 x^{2} - 40 = 0

x = \frac{5}{2}, x = - \frac{5}{2}

Decimal Notation

x = 1.58113 \dots, x = - 1.58113 \dots

Solution steps

16 x^{2} - 40 = 0

Move

40

to the right side

16 x^{2} = 40

Divide both sides by

16

x^{2} = \frac{5}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{5}{2}, x = - \frac{5}{2}

4 x (8 x) + 8 - 12 = 15 x^{2} - 12 (25 + 16)

- 4.9 x^{2} + 16.8 x + 7.6 = 0

w^{2} + 9 = 0

q^{2} - 48 = 0

3 x^{2} + 8 x + 4 = 0

What are the solutions to the equation 16x^2-40=0 ?
The solutions to the equation 16x^2-40=0 are x=sqrt(5/2),x=-sqrt(5/2)
Find the zeros of 16x^2-40=0
The zeros of 16x^2-40=0 are x=sqrt(5/2),x=-sqrt(5/2)