What are the solutions to the equation factor 3x^2+8x+4=0 ?

The solutions to the equation factor 3x^2+8x+4=0 are x=-2/3 ,x=-2

Find the zeros of factor 3x^2+8x+4=0

The zeros of factor 3x^2+8x+4=0 are x=-2/3 ,x=-2

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3 x^{2} + 8 x + 4 = 0

x = - \frac{2}{3}, x = - 2

Solution steps

3 x^{2} + 8 x + 4 = 0

Factor

3 x^{2} + 8 x + 4 : (3 x + 2) (x + 2)

(3 x + 2) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 2 = 0 or x + 2 = 0

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

Solve

x + 2 = 0 : x = - 2

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = - 2

2 x - 3 = x^{2} - 6 x + 9

n^{2} = - 3 n

\frac{1}{4} (x + 2)^{2} - 2 = 3

2 \cdot x^{2} + x = 15

4 y - 20 y^{2} = 0

What are the solutions to the equation factor 3x^2+8x+4=0 ?
The solutions to the equation factor 3x^2+8x+4=0 are x=-2/3 ,x=-2
Find the zeros of factor 3x^2+8x+4=0
The zeros of factor 3x^2+8x+4=0 are x=-2/3 ,x=-2