What are the solutions to the equation 7x-3+8x^2=7+4x^2-x ?

The solutions to the equation 7x-3+8x^2=7+4x^2-x are x=(-2+sqrt(14))/2 ,x=-(2+sqrt(14))/2

Find the zeros of 7x-3+8x^2=7+4x^2-x

The zeros of 7x-3+8x^2=7+4x^2-x are x=(-2+sqrt(14))/2 ,x=-(2+sqrt(14))/2

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7 x - 3 + 8 x^{2} = 7 + 4 x^{2} - x

x = \frac{- 2 + 14}{2}, x = - \frac{2 + 14}{2}

Solution steps

7 x - 3 + 8 x^{2} = 7 + 4 x^{2} - x

Move

x

to the left side

8 x^{2} + 8 x - 3 = 7 + 4 x^{2}

Move

4 x^{2}

to the left side

4 x^{2} + 8 x - 3 = 7

Move

7

to the left side

4 x^{2} + 8 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 ( - 10 )}{2 \cdot 4}

8^{2} - 4 \cdot 4 (- 10) = 414

x_{1, 2} = \frac{- 8 \pm 4 14}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 8 + 4 14}{2 \cdot 4}, x_{2} = \frac{- 8 - 4 14}{2 \cdot 4}

x = \frac{- 8 + 4 14}{2 \cdot 4} : \frac{- 2 + 14}{2}

x = \frac{- 8 - 4 14}{2 \cdot 4} : - \frac{2 + 14}{2}

The solutions to the quadratic equation are:

x = \frac{- 2 + 14}{2}, x = - \frac{2 + 14}{2}

x (x - 6) + 5 (x + 8) = - 2 (3 x - 32)

x^{2} = \frac{81}{100}

x, x^{2} - 9 x + 20 = y

2 s^{2} = 5 s + 3

x^{2} = \frac{81}{169}

What are the solutions to the equation 7x-3+8x^2=7+4x^2-x ?
The solutions to the equation 7x-3+8x^2=7+4x^2-x are x=(-2+sqrt(14))/2 ,x=-(2+sqrt(14))/2
Find the zeros of 7x-3+8x^2=7+4x^2-x
The zeros of 7x-3+8x^2=7+4x^2-x are x=(-2+sqrt(14))/2 ,x=-(2+sqrt(14))/2