What are the solutions to the equation solvefor x,x^2-9x+20=y ?

The solutions to the equation solvefor x,x^2-9x+20=y are x=(9+sqrt(4y+1))/2 ,x=(9-sqrt(4y+1))/2

Find the zeros of solvefor x,x^2-9x+20=y

The zeros of solvefor x,x^2-9x+20=y are x=(9+sqrt(4y+1))/2 ,x=(9-sqrt(4y+1))/2

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solve for

x, x^{2} - 9 x + 20 = y

x = \frac{9 + 4 y + 1}{2}, x = \frac{9 - 4 y + 1}{2}

Solution steps

x^{2} - 9 x + 20 = y

Move

y

to the left side

x^{2} - 9 x + 20 - y = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( 20 - y )}{2 \cdot 1}

Simplify

(- 9)^{2} - 4 \cdot 1 \cdot (20 - y) : 4 y + 1

x_{1, 2} = \frac{- ( - 9 ) \pm 4 y + 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 4 y + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 4 y + 1}{2 \cdot 1}

x = \frac{- ( - 9 ) + 4 y + 1}{2 \cdot 1} : \frac{9 + 4 y + 1}{2}

x = \frac{- ( - 9 ) - 4 y + 1}{2 \cdot 1} : \frac{9 - 4 y + 1}{2}

The solutions to the quadratic equation are:

x = \frac{9 + 4 y + 1}{2}, x = \frac{9 - 4 y + 1}{2}

2 s^{2} = 5 s + 3

x^{2} = \frac{81}{169}

5 x^{2} - 4 x - 10 = 0

2 x^{2} = 6 x - 6

12 x^{2} - 72 x - 84 = 0

What are the solutions to the equation solvefor x,x^2-9x+20=y ?
The solutions to the equation solvefor x,x^2-9x+20=y are x=(9+sqrt(4y+1))/2 ,x=(9-sqrt(4y+1))/2
Find the zeros of solvefor x,x^2-9x+20=y
The zeros of solvefor x,x^2-9x+20=y are x=(9+sqrt(4y+1))/2 ,x=(9-sqrt(4y+1))/2