What are the solutions to the equation 12x^2-72x-84=0 ?

The solutions to the equation 12x^2-72x-84=0 are x=7,x=-1

Find the zeros of 12x^2-72x-84=0

The zeros of 12x^2-72x-84=0 are x=7,x=-1

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12 x^{2} - 72 x - 84 = 0

x = 7, x = - 1

Solution steps

12 x^{2} - 72 x - 84 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 72 ) \pm ( - 72 ) ^{2} - 4 \cdot 12 ( - 84 )}{2 \cdot 12}

(- 72)^{2} - 4 \cdot 12 (- 84) = 96

x_{1, 2} = \frac{- ( - 72 ) \pm 96}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 72 ) + 96}{2 \cdot 12}, x_{2} = \frac{- ( - 72 ) - 96}{2 \cdot 12}

x = \frac{- ( - 72 ) + 96}{2 \cdot 12} : 7

x = \frac{- ( - 72 ) - 96}{2 \cdot 12} : - 1

The solutions to the quadratic equation are:

x = 7, x = - 1

n^{2} - 159 = 10

x^{2} + 18 = - 6 x

- 4 x^{2} = - 8

x^{2} + 2 x^{2} = 16

- 72 (1 + x)^{(2)} + 170 (1 + x) + 100 = 0

What are the solutions to the equation 12x^2-72x-84=0 ?
The solutions to the equation 12x^2-72x-84=0 are x=7,x=-1
Find the zeros of 12x^2-72x-84=0
The zeros of 12x^2-72x-84=0 are x=7,x=-1