What are the solutions to the equation -6x^2+24x-504=0 ?

The solutions to the equation -6x^2+24x-504=0 are x=2-4sqrt(5)i,x=2+4sqrt(5)i

Find the zeros of -6x^2+24x-504=0

The zeros of -6x^2+24x-504=0 are x=2-4sqrt(5)i,x=2+4sqrt(5)i

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- 6 x^{2} + 24 x - 504 = 0

x = 2 - 45 i, x = 2 + 45 i

Solution steps

- 6 x^{2} + 24 x - 504 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 ( - 6 ) ( - 504 )}{2 ( - 6 )}

Simplify

2 4^{2} - 4 (- 6) (- 504) : 485 i

x_{1, 2} = \frac{- 24 \pm 48 5 i}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 24 + 48 5 i}{2 ( - 6 )}, x_{2} = \frac{- 24 - 48 5 i}{2 ( - 6 )}

x = \frac{- 24 + 48 5 i}{2 ( - 6 )} : 2 - 45 i

x = \frac{- 24 - 48 5 i}{2 ( - 6 )} : 2 + 45 i

The solutions to the quadratic equation are:

x = 2 - 45 i, x = 2 + 45 i

15 x^{2} - 23 x - 28 = 0

150 = 50 x + x^{2}

j (x) = x^{2} - x + 1, j (2 a)

x, x^{2} + 2 x^{2} y + 3 x y = 0

2 t^{2} + 3 t - 1 = 0

What are the solutions to the equation -6x^2+24x-504=0 ?
The solutions to the equation -6x^2+24x-504=0 are x=2-4sqrt(5)i,x=2+4sqrt(5)i
Find the zeros of -6x^2+24x-504=0
The zeros of -6x^2+24x-504=0 are x=2-4sqrt(5)i,x=2+4sqrt(5)i