What are the solutions to the equation 150=50x+x^2 ?

The solutions to the equation 150=50x+x^2 are x=5(sqrt(31)-5),x=-5(5+sqrt(31))

Find the zeros of 150=50x+x^2

The zeros of 150=50x+x^2 are x=5(sqrt(31)-5),x=-5(5+sqrt(31))

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150 = 50 x + x^{2}

x = 5 (31 - 5), x = - 5 (5 + 31)

Solution steps

150 = 50 x + x^{2}

Switch sides

50 x + x^{2} = 150

Move

150

to the left side

50 x + x^{2} - 150 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 50 x - 150 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 \cdot 1 \cdot ( - 150 )}{2 \cdot 1}

5 0^{2} - 4 \cdot 1 \cdot (- 150) = 1031

x_{1, 2} = \frac{- 50 \pm 10 31}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 50 + 10 31}{2 \cdot 1}, x_{2} = \frac{- 50 - 10 31}{2 \cdot 1}

x = \frac{- 50 + 10 31}{2 \cdot 1} : 5 (31 - 5)

x = \frac{- 50 - 10 31}{2 \cdot 1} : - 5 (5 + 31)

The solutions to the quadratic equation are:

x = 5 (31 - 5), x = - 5 (5 + 31)

j (x) = x^{2} - x + 1, j (2 a)

x, x^{2} + 2 x^{2} y + 3 x y = 0

2 t^{2} + 3 t - 1 = 0

(x^{2} + 3 x + 2) 2 - 8 (x^{2} + 3 x) = 4

2 x^{2} + 3 = 49

What are the solutions to the equation 150=50x+x^2 ?
The solutions to the equation 150=50x+x^2 are x=5(sqrt(31)-5),x=-5(5+sqrt(31))
Find the zeros of 150=50x+x^2
The zeros of 150=50x+x^2 are x=5(sqrt(31)-5),x=-5(5+sqrt(31))