What are the solutions to the equation 11x^2-12x+1=0 ?

The solutions to the equation 11x^2-12x+1=0 are x=1,x= 1/11

Find the zeros of 11x^2-12x+1=0

The zeros of 11x^2-12x+1=0 are x=1,x= 1/11

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11 x^{2} - 12 x + 1 = 0

x = 1, x = \frac{1}{11}

Solution steps

11 x^{2} - 12 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 11 \cdot 1}{2 \cdot 11}

(- 12)^{2} - 4 \cdot 11 \cdot 1 = 10

x_{1, 2} = \frac{- ( - 12 ) \pm 10}{2 \cdot 11}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 10}{2 \cdot 11}, x_{2} = \frac{- ( - 12 ) - 10}{2 \cdot 11}

x = \frac{- ( - 12 ) + 10}{2 \cdot 11} : 1

x = \frac{- ( - 12 ) - 10}{2 \cdot 11} : \frac{1}{11}

The solutions to the quadratic equation are:

x = 1, x = \frac{1}{11}

x^{2} + 20 x - 200 = 0

3 x^{2} - 2 x - 1 = 0

5 x^{2} + 4 x = 3

5 x^{2} + 4 x = 4

1 x^{2} + b x + c = 0

What are the solutions to the equation 11x^2-12x+1=0 ?
The solutions to the equation 11x^2-12x+1=0 are x=1,x= 1/11
Find the zeros of 11x^2-12x+1=0
The zeros of 11x^2-12x+1=0 are x=1,x= 1/11