What are the solutions to the equation (x-4)(x-6)=-1 ?

The solutions to the equation (x-4)(x-6)=-1 are x=5

Find the zeros of (x-4)(x-6)=-1

The zeros of (x-4)(x-6)=-1 are x=5

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(x - 4) (x - 6) = - 1

x = 5

Solution steps

(x - 4) (x - 6) = - 1

Expand

(x - 4) (x - 6) : x^{2} - 10 x + 24

x^{2} - 10 x + 24 = - 1

Move

1

to the left side

x^{2} - 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 10 )}{2 \cdot 1}

\frac{- ( - 10 )}{2 \cdot 1} = 5

x = 5

The solution to the quadratic equation is:

x = 5

3 x^{2} + 9 x

x, 10 x^{2} - 8 y - 8 y^{3} = 0

7 x + 1 = (2 x - 1)^{2}

(x - 1)^{2} + 7 = 56

2 b^{2} + 8 b - 19 = 5

What are the solutions to the equation (x-4)(x-6)=-1 ?
The solutions to the equation (x-4)(x-6)=-1 are x=5
Find the zeros of (x-4)(x-6)=-1
The zeros of (x-4)(x-6)=-1 are x=5