What are the solutions to the equation 2b^2+8b-19=5 ?

The solutions to the equation 2b^2+8b-19=5 are b=2,b=-6

Find the zeros of 2b^2+8b-19=5

The zeros of 2b^2+8b-19=5 are b=2,b=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 b^{2} + 8 b - 19 = 5

b = 2, b = - 6

Solution steps

2 b^{2} + 8 b - 19 = 5

Move

5

to the left side

2 b^{2} + 8 b - 24 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 ( - 24 )}{2 \cdot 2}

8^{2} - 4 \cdot 2 (- 24) = 16

b_{1, 2} = \frac{- 8 \pm 16}{2 \cdot 2}

Separate the solutions

b_{1} = \frac{- 8 + 16}{2 \cdot 2}, b_{2} = \frac{- 8 - 16}{2 \cdot 2}

b = \frac{- 8 + 16}{2 \cdot 2} : 2

b = \frac{- 8 - 16}{2 \cdot 2} : - 6

The solutions to the quadratic equation are:

b = 2, b = - 6

- x^{2} + 11 x = 28

18 x - 3 x^{2} = 27

(x - 4)^{3} - (x - 3)^{3} = 343

(x + 2)^{2} = x + 2

(\frac{9}{41})^{2} + y^{2} = 1

What are the solutions to the equation 2b^2+8b-19=5 ?
The solutions to the equation 2b^2+8b-19=5 are b=2,b=-6
Find the zeros of 2b^2+8b-19=5
The zeros of 2b^2+8b-19=5 are b=2,b=-6