What are the solutions to the equation 3x-2x^2-7=0 ?

The solutions to the equation 3x-2x^2-7=0 are x= 3/4-i(sqrt(47))/4 ,x= 3/4+i(sqrt(47))/4

Find the zeros of 3x-2x^2-7=0

The zeros of 3x-2x^2-7=0 are x= 3/4-i(sqrt(47))/4 ,x= 3/4+i(sqrt(47))/4

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3 x - 2 x^{2} - 7 = 0

x = \frac{3}{4} - i \frac{47}{4}, x = \frac{3}{4} + i \frac{47}{4}

Solution steps

3 x - 2 x^{2} - 7 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} + 3 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 2 ) ( - 7 )}{2 ( - 2 )}

Simplify

3^{2} - 4 (- 2) (- 7) : 47 i

x_{1, 2} = \frac{- 3 \pm 47 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 3 + 47 i}{2 ( - 2 )}, x_{2} = \frac{- 3 - 47 i}{2 ( - 2 )}

x = \frac{- 3 + 47 i}{2 ( - 2 )} : \frac{3}{4} - i \frac{47}{4}

x = \frac{- 3 - 47 i}{2 ( - 2 )} : \frac{3}{4} + i \frac{47}{4}

The solutions to the quadratic equation are:

x = \frac{3}{4} - i \frac{47}{4}, x = \frac{3}{4} + i \frac{47}{4}

d^{2} = \frac{6 \cdot 4}{31415}

2 x^{2} + 4 x - 1 = 0

x^{2} + 1 - 3 x = 0

2 f (a) = 3 x^{2} - x + 2

12 x + 3 = - 4 x^{2} + 20

What are the solutions to the equation 3x-2x^2-7=0 ?
The solutions to the equation 3x-2x^2-7=0 are x= 3/4-i(sqrt(47))/4 ,x= 3/4+i(sqrt(47))/4
Find the zeros of 3x-2x^2-7=0
The zeros of 3x-2x^2-7=0 are x= 3/4-i(sqrt(47))/4 ,x= 3/4+i(sqrt(47))/4