What are the solutions to the equation x^2+1-3x=0 ?

The solutions to the equation x^2+1-3x=0 are x=(3+sqrt(5))/2 ,x=(3-sqrt(5))/2

Find the zeros of x^2+1-3x=0

The zeros of x^2+1-3x=0 are x=(3+sqrt(5))/2 ,x=(3-sqrt(5))/2

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x^{2} + 1 - 3 x = 0

x = \frac{3 + 5}{2}, x = \frac{3 - 5}{2}

Solution steps

x^{2} + 1 - 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 3 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 1 = 5

x_{1, 2} = \frac{- ( - 3 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 5}{2 \cdot 1}

x = \frac{- ( - 3 ) + 5}{2 \cdot 1} : \frac{3 + 5}{2}

x = \frac{- ( - 3 ) - 5}{2 \cdot 1} : \frac{3 - 5}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 5}{2}, x = \frac{3 - 5}{2}

2 f (a) = 3 x^{2} - x + 2

12 x + 3 = - 4 x^{2} + 20

(x + 3) 2 = 8 (x - 2) + x^{2}

x^{2} + 13 x + 24 = 0

2 b^{2} + 40 = 0

What are the solutions to the equation x^2+1-3x=0 ?
The solutions to the equation x^2+1-3x=0 are x=(3+sqrt(5))/2 ,x=(3-sqrt(5))/2
Find the zeros of x^2+1-3x=0
The zeros of x^2+1-3x=0 are x=(3+sqrt(5))/2 ,x=(3-sqrt(5))/2