What are the solutions to the equation 2b^2+40=0 ?

The solutions to the equation 2b^2+40=0 are b=2sqrt(5)i,b=-2sqrt(5)i

Find the zeros of 2b^2+40=0

The zeros of 2b^2+40=0 are b=2sqrt(5)i,b=-2sqrt(5)i

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2 b^{2} + 40 = 0

b = 25 i, b = - 25 i

Solution steps

2 b^{2} + 40 = 0

Move

40

to the right side

2 b^{2} = - 40

Divide both sides by

2

b^{2} = - 20

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = - 20, b = - - 20

- 20 = 25 i

- - 20 = - 25 i

b = 25 i, b = - 25 i

(\frac{5}{13})^{2} + x^{2} = 1

6 s^{2} + 18 s = 0

5 x^{2} - 72 = 4 x^{2}

x^{2} - 16 x + 2 = 0

3 x^{2} - 3 = 8 x

What are the solutions to the equation 2b^2+40=0 ?
The solutions to the equation 2b^2+40=0 are b=2sqrt(5)i,b=-2sqrt(5)i
Find the zeros of 2b^2+40=0
The zeros of 2b^2+40=0 are b=2sqrt(5)i,b=-2sqrt(5)i