What are the solutions to the equation 1/7 x^2-3=4 ?

The solutions to the equation 1/7 x^2-3=4 are x=7,x=-7

Find the zeros of 1/7 x^2-3=4

The zeros of 1/7 x^2-3=4 are x=7,x=-7

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\frac{1}{7} x^{2} - 3 = 4

x = 7, x = - 7

Solution steps

\frac{1}{7} x^{2} - 3 = 4

Move

3

to the right side

\frac{1}{7} x^{2} = 7

Multiply both sides by

7

x^{2} = 49

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 49, x = - 49

49 = 7

- 49 = - 7

x = 7, x = - 7

x, y = x^{2} - 20 x

3 x^{2} + 14 x - 1 = 7 x - 3

3 x^{2} + 10 x + 20 = 10 - 3 x

x, f (x + 2) = 4 x^{2} + 3

2 x^{2} - 10 x + 10 = 0

What are the solutions to the equation 1/7 x^2-3=4 ?
The solutions to the equation 1/7 x^2-3=4 are x=7,x=-7
Find the zeros of 1/7 x^2-3=4
The zeros of 1/7 x^2-3=4 are x=7,x=-7