What are the solutions to the equation y^2=24y ?

The solutions to the equation y^2=24y are y=24,y=0

Find the zeros of y^2=24y

The zeros of y^2=24y are y=24,y=0

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y^{2} = 24 y

y = 24, y = 0

Solution steps

y^{2} = 24 y

Move

24 y

to the left side

y^{2} - 24 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 24)^{2} - 4 \cdot 1 \cdot 0 = 24

y_{1, 2} = \frac{- ( - 24 ) \pm 24}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 24 ) + 24}{2 \cdot 1}, y_{2} = \frac{- ( - 24 ) - 24}{2 \cdot 1}

y = \frac{- ( - 24 ) + 24}{2 \cdot 1} : 24

y = \frac{- ( - 24 ) - 24}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

y = 24, y = 0

4 x (x - 6) = 5

4 x (x - 6) = 7

2 x^{2} = 10 x + 48

x, x^{2} - 2 x - 5 = 0

10 x^{2} - 6 = 11 x

What are the solutions to the equation y^2=24y ?
The solutions to the equation y^2=24y are y=24,y=0
Find the zeros of y^2=24y
The zeros of y^2=24y are y=24,y=0