What are the solutions to the equation solvefor x,x^2-2x-5=0 ?

The solutions to the equation solvefor x,x^2-2x-5=0 are x=1+sqrt(6),x=1-sqrt(6)

Find the zeros of solvefor x,x^2-2x-5=0

The zeros of solvefor x,x^2-2x-5=0 are x=1+sqrt(6),x=1-sqrt(6)

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x, x^{2} - 2 x - 5 = 0

x = 1 + 6, x = 1 - 6

Decimal Notation

x = 3.44948 \dots, x = - 1.44948 \dots

Solution steps

x^{2} - 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 5) = 26

x_{1, 2} = \frac{- ( - 2 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 6}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 6}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 6}{2 \cdot 1} : 1 + 6

x = \frac{- ( - 2 ) - 2 6}{2 \cdot 1} : 1 - 6

The solutions to the quadratic equation are:

x = 1 + 6, x = 1 - 6

10 x^{2} - 6 = 11 x

(x + 8) (x - 4) = 0

81 r^{2} - 3 = 0

(7 - 3 x)^{2} = \frac{9}{16}

2 m^{2} + 3 m + 4 = 0

What are the solutions to the equation solvefor x,x^2-2x-5=0 ?
The solutions to the equation solvefor x,x^2-2x-5=0 are x=1+sqrt(6),x=1-sqrt(6)
Find the zeros of solvefor x,x^2-2x-5=0
The zeros of solvefor x,x^2-2x-5=0 are x=1+sqrt(6),x=1-sqrt(6)