What are the solutions to the equation 207=2x^2+7 ?

The solutions to the equation 207=2x^2+7 are x=10,x=-10

Find the zeros of 207=2x^2+7

The zeros of 207=2x^2+7 are x=10,x=-10

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207 = 2 x^{2} + 7

x = 10, x = - 10

Solution steps

207 = 2 x^{2} + 7

Switch sides

2 x^{2} + 7 = 207

Move

7

to the right side

2 x^{2} = 200

Divide both sides by

2

x^{2} = 100

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 100, x = - 100

100 = 10

- 100 = - 10

x = 10, x = - 10

x, f^{- 1} (x) = x^{2} + 4 x

- 3 x^{2} + 30 x = 0

- 0.25 x^{2} + 350 x - 120000 = 0

4 - 5 b^{2} = - 176

(x - 2)^{2} - 81 = 0

What are the solutions to the equation 207=2x^2+7 ?
The solutions to the equation 207=2x^2+7 are x=10,x=-10
Find the zeros of 207=2x^2+7
The zeros of 207=2x^2+7 are x=10,x=-10