What are the solutions to the equation -0.25x^2+350x-120000=0 ?

The solutions to the equation -0.25x^2+350x-120000=0 are x=600,x=800

Find the zeros of -0.25x^2+350x-120000=0

The zeros of -0.25x^2+350x-120000=0 are x=600,x=800

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- 0.25 x^{2} + 350 x - 120000 = 0

x = 600, x = 800

Solution steps

- 0.25 x^{2} + 350 x - 120000 = 0

Multiply both sides by

100

- 25 x^{2} + 35000 x - 12000000 = 0

Factor

- 25 x^{2} + 35000 x - 12000000 : - 25 (x - 600) (x - 800)

- 25 (x - 600) (x - 800) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 600 = 0 or x - 800 = 0

Solve

x - 600 = 0 : x = 600

Solve

x - 800 = 0 : x = 800

The solutions to the quadratic equation are:

x = 600, x = 800

4 - 5 b^{2} = - 176

(x - 2)^{2} - 81 = 0

x^{2} + 25 = - 9 x + 5

w^{2} - 7 w - 30 = 0

0 = 2 - x^{2}

What are the solutions to the equation -0.25x^2+350x-120000=0 ?
The solutions to the equation -0.25x^2+350x-120000=0 are x=600,x=800
Find the zeros of -0.25x^2+350x-120000=0
The zeros of -0.25x^2+350x-120000=0 are x=600,x=800