What are the solutions to the equation w^2-7w-30=0 ?

The solutions to the equation w^2-7w-30=0 are w=10,w=-3

Find the zeros of w^2-7w-30=0

The zeros of w^2-7w-30=0 are w=10,w=-3

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w^{2} - 7 w - 30 = 0

w = 10, w = - 3

Solution steps

w^{2} - 7 w - 30 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 30 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 30) = 13

w_{1, 2} = \frac{- ( - 7 ) \pm 13}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 7 ) + 13}{2 \cdot 1}, w_{2} = \frac{- ( - 7 ) - 13}{2 \cdot 1}

w = \frac{- ( - 7 ) + 13}{2 \cdot 1} : 10

w = \frac{- ( - 7 ) - 13}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

w = 10, w = - 3

0 = 2 - x^{2}

2 x^{2} + 5 = 25

x^{2} + 16 x - 57 = 0

x, 6 x^{2} + 12 x + 5 = 0

x, f (x + 1) = x^{2} - 3 x + 2

What are the solutions to the equation w^2-7w-30=0 ?
The solutions to the equation w^2-7w-30=0 are w=10,w=-3
Find the zeros of w^2-7w-30=0
The zeros of w^2-7w-30=0 are w=10,w=-3